The Purplemath Forums

by **crescentcitycid** on Sun Feb 27, 2011 10:28 pm

If I had the function R=2.3log(A+3000)-5.1 and I wanted solve for A in terms of R, would A=10^{((R/2.3)-5.1))}-3000 be correct?

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by **stapel_eliz** on Sun Feb 27, 2011 10:40 pm

crescentcitycid wrote:If I had the function R=2.3log(A+3000)-5.1 and I wanted solve for A in terms of R, would A=10^{((R/2.3)-5.1))}-3000 be correct?

No; the solution method does not start with dividing through by 2.3.

Try doing each individual step carefully. :wink:

by **crescentcitycid** on Sun Feb 27, 2011 10:57 pm

Ah, I should start with adding the 5.1 then?

by **stapel_eliz** on Mon Feb 28, 2011 12:50 am

crescentcitycid wrote:Ah, I should start with adding the 5.1 then?

Yes.

Rewriting a logarithmic function