## How do I find the nth term of this sequence?

Complex numbers, rational functions, logarithms, sequences and series, matrix operations, etc.

### How do I find the nth term of this sequence?

I have the sequence 2,8,26,80,242
So b sub n = 6,18,54,162
b sub 1 = 6
r = 3
using the geometric formula I have 6 times 3^(n-1).
rogermiranda

Posts: 19
Joined: Fri Apr 30, 2010 6:01 pm

### Re: How do I find the nth term of this sequence?

rogermiranda wrote:I have the sequence 2,8,26,80,242
So b sub n = 6,18,54,162
b sub 1 = 6
r = 3
using the geometric formula I have 6 times 3^(n-1).

3,9,27,81,243..

=$3^1,3^2,3^3,3^4,3^5,...$

your sequence is one less per term

so the nth term is $3^n-1$

Martingale

Posts: 350
Joined: Mon Mar 30, 2009 1:30 pm
Location: USA

rogermiranda wrote:I have the sequence 2,8,26,80,242
So b sub n = 6,18,54,162

How does your "so" statement relate to the given sequence?

stapel_eliz

Posts: 1715
Joined: Mon Dec 08, 2008 4:22 pm