The question I am stuck on is log 4{sqrt}32y

i know if there is no base shown it is log base 10, but when i plug it into my calculator I get zero for my answer.

How do i go about solving this question?

4 posts
• Page **1** of **1**

The question I am stuck on is log 4{sqrt}32y

i know if there is no base shown it is log base 10, but when i plug it into my calculator I get zero for my answer.

How do i go about solving this question?

i know if there is no base shown it is log base 10, but when i plug it into my calculator I get zero for my answer.

How do i go about solving this question?

- heather
**Posts:**2**Joined:**Tue Mar 16, 2010 3:59 pm

"solving" means an equation. did you mean "simplify" or "expand" or "evaluate" or something?

is the base 10? or 4? what is inside the {sqrt}?

thnx

is the base 10? or 4? what is inside the {sqrt}?

thnx

- nicknation
**Posts:**24**Joined:**Wed Mar 11, 2009 3:28 pm

I'm sorry,

the base is 10, and its supposed to be the square root of 32y.

I'm sorry, I'm still getting the hang of posting math language, but I am getting there.

And the question says "express each as a sum, difference or multiple of logarithms. Wherever possible, evaluate logarithms of the result."

the base is 10, and its supposed to be the square root of 32y.

I'm sorry, I'm still getting the hang of posting math language, but I am getting there.

And the question says "express each as a sum, difference or multiple of logarithms. Wherever possible, evaluate logarithms of the result."

- heather
**Posts:**2**Joined:**Tue Mar 16, 2010 3:59 pm

so you're supposed to expand log_{10}(4 * sqrt[32y]) ?

the sqrt[32] is sqrt[2 * 16] = 4 * sqrt[2]

the sqrt[] is the 1/2 power

to expand use the rules they show here

you can evaluate the log_{10}(16) and the (1/2) * log_{10}(2) but not the (1/2) * log_{10}(y)

the sqrt[32] is sqrt[2 * 16] = 4 * sqrt[2]

the sqrt[] is the 1/2 power

to expand use the rules they show here

you can evaluate the log

- nicknation
**Posts:**24**Joined:**Wed Mar 11, 2009 3:28 pm

4 posts
• Page **1** of **1**