rewrite 3 log x - 2 log (x^2+1) +5 log (x-1) as single log

[opera_elle]

Rewrite the expression
3 log x - 2 log (x^2+1) +5 log (x-1)
as a single logarithm \log A. Then the function
A=???

[maggiemagnet]

Rewrite the expression
3 log x - 2 log (x^2+1) +5 log (x-1)
as a single logarithm \log A. Then the function
A=???

The rewriting uses the rules they gave you. (You can review them here.) For example, 3log(x) turns into log(x³), and log(x³) - log((x² + 1)²) becomes log(x³ / ((x² + 1)²).

But I don't understand what is meant by "\log A", nor what function they're referring to. How does A relate to the various logarithms?