Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
Hans27
Posts: 3
Joined: Thu Jul 14, 2016 11:40 am
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Hello there folks
pardon my ignorance

but i was trying to solve a simple integral

but then at the moment 3:34 he states that x/sqr(x) is equal to sqrt(x)

which i obviously believe
i typed x/sqrt(x) in wolfram alpha and it also gave me the result sqrt(x)

but i don't understand why

could any of you folks prove it to me in a (or more than one) simple explanation?

Thanks a lot!

nona.m.nona
Posts: 288
Joined: Sun Dec 14, 2008 11:07 pm
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...he states that x/sqr(x) is equal to sqrt(x)

which i obviously believe
i typed x/sqrt(x) in wolfram alpha and it also gave me the result sqrt(x)

but i don't understand why
What did you get when you did the simplification? You noted that:

$\sqrt{ x^2\,}\, =\, x$

(for non-negative x) so:

$x\, =\, \left(\sqrt{ x\,}\right)^2$

What did you do next? Please be complete. Thank you.

Hans27
Posts: 3
Joined: Thu Jul 14, 2016 11:40 am
Contact: