how to work this problem: 3/a²+a × 2a+2/6

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.

how to work this problem: 3/a²+a × 2a+2/6

3/a²+a × 2a+2/6
martaw7

Posts: 4
Joined: Wed Jul 22, 2009 5:30 pm

martaw7 wrote:3/a²+a × 2a+2/6

As posted, the expression appears to be:

. . . . .$\frac{3}{a^2}\, +\, (a)\times(2a)\, +\, \frac{2}{6}$

Thank you!

stapel_eliz

Posts: 1729
Joined: Mon Dec 08, 2008 4:22 pm

Re: how to work this problem: 3/a²+a × 2a+2/6

Perform the indicated operation

3 is over a squared +a x 2a+2 over 6
martaw7

Posts: 4
Joined: Wed Jul 22, 2009 5:30 pm

Re: how to work this problem: 3/a²+a × 2a+2/6

Still a little vague. As written you could mean:

$\frac{3}{a^2} + (a)\left(\frac{2a+2}{6}\right)$

or
$\frac{3}{a^2+a}\left(\frac{2a+2}{6}\right)$

or what Stapel_eliz wrote or three or four other possibilities (English is tricky, ain't it?).

So, use grouping symbols like parentheses: "3 is over (a squared + a)" and such. Help us see what the entire numerators and denominators are.
Honeysuckle588

Posts: 23
Joined: Wed Jul 15, 2009 4:07 pm

Re: how to work this problem: 3/a²+a × 2a+2/6

answere is a^4 + a^3 + 9 all divided by 3a^2. if you want to see every step, go to www.wolfram.com and type in the information and it will show you every step.
milynx

Posts: 7
Joined: Mon Jul 27, 2009 9:46 pm