last bit of a quadradic... solving 4x^2 + x -1/4 = 0  TOPIC_SOLVED

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.

last bit of a quadradic... solving 4x^2 + x -1/4 = 0

Postby balkenator on Sat Jun 20, 2009 1:22 pm

I'm having trouble figuring out how to simplify the last bit of this quadradic equation: 4x^2 + x -1/4 = 0

I've gotten down to x + 1/4 = + or - the square root of 1/32 (sorry i'm new on this board and don't really know how to write it out)... is the answer already simplfied (it doesn't seem like it) or can I go further? I would not remember how to simplfy the square root of 1/32. :oops:

Thanks
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Postby stapel_eliz on Sat Jun 20, 2009 2:59 pm

Would it be correct to assume that the instructions for this equations specify that you must solve by completing the square, rather than any other method?

If so, then:

. . . . .

. . . . .

. . . . .

. . . . .

. . . . .

. . . . .

...and so forth. :wink:
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Re: last bit of a quadradic... solving 4x^2 + x -1/4 = 0  TOPIC_SOLVED

Postby balkenator on Sat Jun 20, 2009 8:02 pm

OMG I was stuck in a rut- i totally see it now... thank you so much!
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