Simplify n^2-81/(n+9)^2 by removing factors of 1

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Pat Oliver
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Simplify n^2-81/(n+9)^2 by removing factors of 1

Postby Pat Oliver » Fri Jun 05, 2009 5:48 am

Simplify by removing factors of 1: n^2-81/(n+9)^2

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stapel_eliz
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Postby stapel_eliz » Fri Jun 05, 2009 10:43 am

Factor the difference of squares in the numerator.

Then cancel the one common factor.

If you get stuck, please reply showing how far you have gotten. Thank you! :D

Pat Oliver
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Re: Simplify n^2-81/(n+9)^2 by removing factors of 1

Postby Pat Oliver » Sat Jun 06, 2009 1:47 am

This is what I could do: n^2-81/(n+9)^2
factor numerator: (n-9)(n+9)
factor denominator: (n+9)^2

I'm stuck!

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stapel_eliz
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Postby stapel_eliz » Sat Jun 06, 2009 10:58 am

Note that "squared" means "times itself", factor the denominator, and cancel the one common factor. :wink:


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