[SPLIT] finding vertex, direction from y=ax^2+bx+c  TOPIC_SOLVED

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[SPLIT] finding vertex, direction from y=ax^2+bx+c

Postby pistolpete on Thu May 28, 2009 10:52 pm

My next section is a bit different and once again I have no clue what to do. In the book it says :

"Find the coordinates of the vertex then decide if the parabola has a minimum or maximum value."

Ex.1
f(x) = x^2 - 4x + 4

Ex. 2
f(x) = -x^2 - 8x - 16

Can you tell me what to do here?
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Postby stapel_eliz on Fri May 29, 2009 11:29 am

The formula for the vertex is:



...and then f(h) = k. This gives you the coordinates, (h, k). The sign of "a" tells you the direction: for a > 0, the vertex is the minimum because the parabola opens upward; for a < 0, the vertex is the maximum because the parabola opens downward. :wink:
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Re: [SPLIT] finding vertex, direction from y=ax^2+bx+c  TOPIC_SOLVED

Postby pistolpete on Sun May 31, 2009 12:57 am

OKay Thanks You once again I got that now too. :clap: :thumb:
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