sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.

sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?

$sqrt{3}_{x!}\left(\frac{x^2}{5^x}\right)+\left(\frac{4}{23}\right)=?$

stripling_warrior

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Location: California!!!

Re: sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?

Until you're given a value for "x" (and a definition for the subscripted square root notation), there is no way to evaluate this. Sorry!

stapel_eliz

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Joined: Mon Dec 08, 2008 4:22 pm

Re: sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?

I found it in a calculus text book and wanted to know what it meant.

stripling_warrior

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Joined: Wed May 06, 2009 7:42 pm
Location: California!!!