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sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?  TOPIC_SOLVED

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sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?  TOPIC_SOLVED

Postby stripling_warrior on Thu May 07, 2009 8:54 pm

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Re: sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?

Postby stapel_eliz on Thu May 07, 2009 10:12 pm

Until you're given a value for "x" (and a definition for the subscripted square root notation), there is no way to evaluate this. Sorry! :oops:
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Re: sqrt[3]-sub-(x!)*(x^2/5^x) + (4/23) = ?

Postby stripling_warrior on Fri May 08, 2009 6:05 pm

I found it in a calculus text book and wanted to know what it meant.
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