inverse quadratic equations?  TOPIC_SOLVED

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.

inverse quadratic equations?

Postby xkiwibird on Fri May 01, 2009 3:53 am

i'm extremely stuck on this problem.
it's y=x2+x.
i know the first step is switching y and x to get x=y2+y, but i don't know what to do afterwards to inverse it, and i am supposed to use the quardatic equation?
please help, thanks!
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Re: inverse quadratic equations?

Postby Martingale on Fri May 01, 2009 4:13 am

xkiwibird wrote:i'm extremely stuck on this problem.
it's y=x2+x.
i know the first step is switching y and x to get x=y2+y, but i don't know what to do afterwards to inverse it, and i am supposed to use the quardatic equation?
please help, thanks!



You could try completing the square
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  TOPIC_SOLVED

Postby stapel_eliz on Mon May 18, 2009 2:34 pm

xkiwibird wrote:it's y=x2+x.
... i don't know what to do afterwards to inverse it, and i am supposed to use the quardatic equation?

You have x2 + x - y = 0, so a = 1, b = 1, and c = -y. Plug these into the Quadratic Formula to solve for x in terms of y. Then swap the variables, etc, etc.

:wink:
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