This question has three parts. i completed the first two parts but i'm stuck at part three. The question is as follow:

Given that (x-2) is a factor of 3x^3+7x^2+hx-8:

(i) Show that the value of h= -22

Solution: Since (x-2) is a factor, then f(2)=0 therefore substitute 2 wherever x is in the equation

3(2)^3+7(2)^2=h(2)-8

=24+28-8+2h

=2h+44

=2h= -44

=-44/2

=-22

(ii) Factorise completely 3x^3+7x^2+22x-8

I used synthetic division and got 3x^2+13x-4 when factored i got (x-2)(3x-1)(x+4)

(iii) Hence or otherwise solve: 3x^3+7x^2+22x-8=0 This is where i'm stuck. I was never good at equations so i need some help with solving part (iii) of this question. Thanks