how do I go about solving?
log (2x+5) x log (9x^{2})=0
I would start by distributing log to 2x and then log 5? and then go from there?
if the problem ishow do I go about solving?
log (2x+5) x log (9x^{2})=0
I would start by distributing log to 2x and then log 5? and then go from there?
You don't. You know (by factoring, like you learned back when you were studying quadratic equations), that log(2x + 5) = 0. By using what you know about logs, you then converted this log equation into its equivalent exponential equation.how do you know that log 2x+5=1?
how do you know that log 2x+5=1? where you wrote the answer? Is it true that log A * log B = log A + log B =0? I'm not sure where you're getting 2 equations =1?