how do I go about solving?
log (2x+5) x log (9x^{2})=0
I would start by distributing log to 2x and then log 5? and then go from there?
santaclaus wrote:how do I go about solving?
log (2x+5) x log (9x^{2})=0
I would start by distributing log to 2x and then log 5? and then go from there?
santaclaus wrote:how do you know that log 2x+5=1?
santaclaus wrote:how do you know that log 2x+5=1? where you wrote the answer? Is it true that log A * log B = log A + log B =0? I'm not sure where you're getting 2 equations =1?