santaclaus wrote:(again, don't know notation for square root)
Please review the article on
formatting math as text, or else follow the instructions in
the forum posting on LaTeX formatting.
santaclaus wrote:How do I solve and equation like the following?
x^{1.05}=1.09?
I would first do 1.05 log x = log 9
I will guess that you are using the common (base-ten) log, but I'm afraid I don't follow your steps...?
To learn the properties of logs, try
here. But I think your only error is that you changed the "9" to a "1.09", or vice versa.
Then next step in
solving the log equation is to isolate the x-term, and then convert back to exponentials:
. . . . .. . . . .Simplify the left-hand side to just "x", and use your calculator if you need a decimal approximation for the right-hand side.
santaclaus wrote:In sq.rt x+sq.rt.x = 3 here there are 2 square roots in the problem.
There may be two square roots, but unfortunately you haven't used grouping symbols to say where they go. Do you mean either of the following?
. . . . .ln(sqrt(x)) + sqrt(x) = 3
. . . . .ln(sqrt(x) + sqrt(x)) = 3
When you reply, please provide the instructions for this equation, along with a clear listing of everything you have tried so far. Thank you!