santaclaus wrote:I'm trying to find the inverses of these functions:
2. h(x)= log (x-3)
do I take log x and log3?
To learn the basic process for finding inverses of functions, try
here. To learn how to solve log equations, try
here.
Once you have learned the necessary background material, the following should make sense.
Rename "h(x)" as "y".
Solve the log equation for "x=".
Swap the variables.
Rename the new "y" as "h
^{-1}(x)".
santaclaus wrote:3. q(x)=ln(x+3) - ln(x-5)
do I distribute here?
I don't know what you mean by "distributing"...?
To learn the rules for how to combine two log terms into one, try
here.
Once you have learned the necessary background material:
Apply a log rule to combine the subtracted log terms into one log term.
Rename "q(x)" as "y".
Solve the resulting log equation for "x=".
Swap the variables.
Rename the new "y" as "q
^{-1}".
santaclaus wrote:4. s(x)=3/2+logx
no idea
Use
the definition of logarithms to convert the fraction 3/2 into a logarithm. Then proceed as above.
If, after you have thoroughly studied all the lessons, you get stuck, please reply showing your work and reasoning so far. Thank you!