graphing: x^2 - 2x - 8 = 0, determinant of x^2 + 2x + 1 = 0,  TOPIC_SOLVED

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.

graphing: x^2 - 2x - 8 = 0, determinant of x^2 + 2x + 1 = 0,

Postby lchilds on Fri Apr 03, 2009 8:08 pm

1: x^2 - 2x - 8 = 0

2: calculate the value of the discriminant of x^2 + 2x + 1 = 0

3: find corresponding y values for x= -4, -3, -2, -1, 0, 1, 2, if y= x^2 + 2x - 15
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Postby stapel_eliz on Fri Apr 03, 2009 9:12 pm

lchilds wrote:1: x^2 - 2x - 8 = 0

To learn how to solve quadratic equations, try here.

lchilds wrote:2: calculate the value of the discriminant of x^2 + 2x + 1 = 0

To learn about the Quadratic Formula, its disciminant, and how to use it, try here.

lchilds wrote:3: find corresponding y values for x= -4, -3, -2, -1, 0, 1, 2, if y= x^2 + 2x - 15

Plug the given x-values into the given formula, and simplify to find the corresponding values of y.

If you get stuck, please reply showing how far you have gotten. Thank you! :D
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