1: x^2 - 2x - 8 = 0

2: calculate the value of the discriminant of x^2 + 2x + 1 = 0

3: find corresponding y values for x= -4, -3, -2, -1, 0, 1, 2, if y= x^2 + 2x - 15

1: x^2 - 2x - 8 = 0

2: calculate the value of the discriminant of x^2 + 2x + 1 = 0

3: find corresponding y values for x= -4, -3, -2, -1, 0, 1, 2, if y= x^2 + 2x - 15

2: calculate the value of the discriminant of x^2 + 2x + 1 = 0

3: find corresponding y values for x= -4, -3, -2, -1, 0, 1, 2, if y= x^2 + 2x - 15

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
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To learn how to solve quadratic equations, try1: x^2 - 2x - 8 = 0

To learn about the Quadratic Formula, its disciminant, and how to use it, try2: calculate the value of the discriminant of x^2 + 2x + 1 = 0

Plug the given x-values into the given formula, and3: find corresponding y values for x= -4, -3, -2, -1, 0, 1, 2, if y= x^2 + 2x - 15

If you get stuck, please reply showing how far you have gotten. Thank you!