## Intermediate Algebra Equation: [x/x+1]/[[x/x+1]+x]]

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
jenhudd1171
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### Intermediate Algebra Equation: [x/x+1]/[[x/x+1]+x]]

Anyone???

[x/x+1]/[[x/x+1]+x]]

maggiemagnet
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Joined: Mon Dec 08, 2008 12:32 am
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### Re: Intermediate Algebra Equation: [x/x+1]/[[x/x+1]+x]]

Anyone???

[x/x+1]/[[x/x+1]+x]]
Your subject line says "equation" but there's no "equals" so this is just an "expression. Also, there weren't any instructions, so I don't know what you're supposed to be doing. Please write back with that information. Also, please say if the brackets mean "floor function", "ceiling function", one of the integer functions, or if they're just brackets for grouping, so the expression means like this:

$\frac{\left(\frac{x}{x}\, +\, 1\right)}{\left(\left(\frac{x}{x}\, +\, 1\right)\, +\, x}$

(The meaning would be different if you'd done like [x/(x+1)]/[[x/(x+1)]+x].) Also, please show what you've tried so far. Thanks!

jenhudd1171
Posts: 2
Joined: Mon Sep 30, 2013 4:17 pm
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### Re: Intermediate Algebra Equation: [x/x+1]/[[x/x+1]+x]]

The question just reads to simplify. Yes, the way you have it written is correct. The brackets are merely for grouping purposes.

[x/x+1]/[[x/x+1]+x]]

I multiplied everything by the common denominator : x (x+1)
My final answer was 1/2+x but I am not sure that was correct. Sometimes all the x's gets me confused.

maggiemagnet
Posts: 358
Joined: Mon Dec 08, 2008 12:32 am
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### Re: Intermediate Algebra Equation: [x/x+1]/[[x/x+1]+x]]

[x/x+1]/[[x/x+1]+x]]
...please say if...they're just brackets for grouping, so the expression means like this:

$\frac{\left(\frac{x}{x}\, +\, 1\right)}{\left(\left(\frac{x}{x}\, +\, 1\right)\, +\, x\right)}$
The question just reads to simplify. Yes, the way you have it written is correct. The brackets are merely for grouping purposes.

[x/x+1]/[[x/x+1]+x]]

I multiplied everything by the common denominator : x (x+1)
$\frac{\left(\frac{x}{x\, +\, 1}\right)}{\left( \frac{x}{x\, +\, 1}\, +\, x \right)}$