plz show how this is done: 3x^2+10x+3/x+3 = x^2-4x+3/x-1  TOPIC_SOLVED

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plz show how this is done: 3x^2+10x+3/x+3 = x^2-4x+3/x-1

Postby Daryl9000 on Mon Oct 08, 2012 10:37 pm

Can someone please show me how this question is done

3x^2+10x+3 = x^2-4x+3
x+3 x-1

the x-1 should be on the other side of the equals sign...
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Re: plz show how this is done: 3x^2+10x+3/x+3 = x^2-4x+3/x-1  TOPIC_SOLVED

Postby maggiemagnet on Tue Oct 09, 2012 11:29 am

Daryl9000 wrote:Can someone please show me how this question is done

3x^2+10x+3 = x^2-4x+3
x+3 x-1

the x-1 should be on the other side of the equals sign...

You can see how to format this (without learning LaTeX) in this article: (3x^2 + 10x + 3)/(x + 3) = (x^2 - 4x + 3)/(x - 1)

You can learn how to solve this sort of equation in this article: Start by factoring and canceling:

((3x + 1)(x + 3))/(x + 3) = ((x - 3)(x - 1))/(x - 1)

Cancel, solve, and then re-check to make sure the solution works!
:clap:
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