Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
jchen24
Posts: 2
Joined: Wed Aug 01, 2012 7:52 pm
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Hey... I'm signed up because I need help on this parabola questions!
Here is my problem:
x^+3x-4=6
x^ is like x squared btw:)
Last edited by jchen24 on Thu Aug 02, 2012 3:14 pm, edited 1 time in total.

stapel_eliz
Posts: 1628
Joined: Mon Dec 08, 2008 4:22 pm
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Here is my problem:
x^+3x-4=6
What are you supposed to do with this equation? Graph it? Find the domain? Find the range? Find the intercepts? Solve using the Quadratic Formula? Find the directrix, focus, or vertex? Or something else?

When you reply, please show what you've tried so far. Thank you!

jchen24
Posts: 2
Joined: Wed Aug 01, 2012 7:52 pm
Contact:

### Re:

Here is my problem:
x^+3x-4=6
What are you supposed to do with this equation? Graph it? Find the domain? Find the range? Find the intercepts? Solve using the Quadratic Formula? Find the directrix, focus, or vertex? Or something else?

When you reply, please show what you've tried so far. Thank you!
I'm supposed to graph the equation and find the vertex.
I've tried doing this to find the vertex:
x^+3x-4=6
x^+3x-10=y <----- Not sure if this is right
Then I did the axis equation and got -3/2.
(-3/2)^+3(-3/2)-10=y
When I solved it, I got -12.25. So for the vertex I got (-3/2, -12.25).

Then I tried a different way to find the vertex:
x^+3x-4=6
y=x^+3x-4
Then I did the axis equation again and got 2.
y=(2)^+3(2)-4
y=6
So for the vertex I got (2,6). The thing is that this is actually one of the points on the parabola... ?
I don't know what I did wrong.