Find the x and y intercepts  TOPIC_SOLVED

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.

Find the x and y intercepts

Postby jpalmer11 on Thu Nov 17, 2011 9:41 am

Hi,

I am having problems with two problems I am hoping someone can point me in the right direction.

First find the x intercepts and y intercepts for f(x)

f(X)=x^2-6x+1

second solve for x

x^2+41=10x (type your answer in the form a+bi)

I understand the basic concepts, but the answers I am coming out with do not look right.
I would be grateful for any help.
Thank You
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Postby stapel_eliz on Thu Nov 17, 2011 3:48 pm

jpalmer11 wrote:First find the x intercepts and y intercepts for f(x)

f(X)=x^2-6x+1

second solve for x

x^2+41=10x (type your answer in the form a+bi)

I understand the basic concepts, but the answers I am coming out with do not look right.

It's hard to find errors in work we can't see. :oops:

Please reply showing what you're "coming out with", and the steps you took to get there. Thank you! :wink:
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Re: Find the x and y intercepts

Postby jpalmer11 on Thu Nov 17, 2011 4:48 pm

Thank you so much for getting back to me. Sorry about that it was real late and I was not thinking clearly. I will as soon as I get home. :confused:
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Re: Find the x and y intercepts

Postby jpalmer11 on Thu Nov 17, 2011 5:30 pm

For f(x)=x^2-6x+1
I think the reason I can not find the X and Y intercepts is there are no intercepts. Is that correct.

on the second problem solve for x
x^2+7x-4=0
can you just let me know if I am heading in the right direction with
- (-10) + 2 the square of 10^2 - 164 devided by 2
Thank You
jpalmer11
 
Posts: 7
Joined: Thu Sep 08, 2011 5:20 pm

  TOPIC_SOLVED

Postby stapel_eliz on Thu Nov 17, 2011 7:23 pm

jpalmer11 wrote:For f(x)=x^2-6x+1
I think the reason I can not find the X and Y intercepts is there are no intercepts. Is that correct.

To find the x-intercept(s), plug zero in for y (in this case, for f(x)) and solve. What do you get?

To find the y-intercept, plug zero in for x and solve. What do you get?

Note: You can also look at the graph to confirm the intercept(s), if any.

jpalmer11 wrote:on the second problem solve for x
x^2+7x-4=0
can you just let me know if I am heading in the right direction with
- (-10) + 2 the square of 10^2 - 164 devided by 2

Your formatting is unclear, and I have no idea what is meant by the squared "plus" sign. Do you maybe mean the following?

. . . . .(-(-10) +/- sqrt[10^2 - 164]) / 2

...which typesets as:

. . . . .

If so, how did you get this? I'm not seeing how this relates to the Quadratic Formula or any other method of solving this quadratic equation (which has a = 1, b = 7, and c = -4)...?
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