Book Question: Find a polynomial f(x) of degree 6 such that 0 and 3 are both zeros of multiplicity 3 and f(2)=-24. Sketch the graph of f.

My Question: I can create the polynomial well enough, but I don't under stand how to make it match up to f(2)=-24.

My work so far:

Zeros: 0, 3

Factors: (x)^3 (x-3)^3

Distributed: f(x)= [x^6] - [9x^5] + [27x^4] - [27x^3]

(I hope I typed this up correctly.)

Now I need to make that polynomial pass through point (2,-24). How do I do that?