Equation of circle with center (3,2) and tangent to y-axis

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tgoace
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Equation of circle with center (3,2) and tangent to y-axis

Postby tgoace » Mon Sep 05, 2011 6:07 am

Find the equation of a circle that has the center (3,2) and is tangent to the y-axis. Write it in the form (x-h)^2 + (y-k)^2

I don't know what to do here. I know tangent means that the line intersect the axis, but I don't have a number here, all I have is "y-axis". What do I do?

nona.m.nona
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Re: Equation of circle with center (3,2) and tangent to y-ax

Postby nona.m.nona » Mon Sep 05, 2011 3:07 pm

tgoace wrote:I know tangent means that the line intersect the axis, but I don't have a number here, all I have is "y-axis".

Not quite: To be "tangent" means that the line touches, but does not cross, the axis. As for a "number", use the x-coordinate for every point on the y-axis. It may be helpful to draw the circle.


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