Hi, can anyone help me with this problem.

The radius of a rectangular cone is "r", and height "h", by what value "x" must "r" be increased and "h" be decreased to keep an identical volume?

Thanks.

Luke.

Hi, can anyone help me with this problem.

The radius of a rectangular cone is "r", and height "h", by what value "x" must "r" be increased and "h" be decreased to keep an identical volume?

Thanks.

Luke.

The radius of a rectangular cone is "r", and height "h", by what value "x" must "r" be increased and "h" be decreased to keep an identical volume?

Thanks.

Luke.

- little_dragon
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Luke53 wrote:The radius of a rectangular cone is "r", and height "h", by what value "x" must "r" be increased and "h" be decreased to keep an identical volume?

i think U do like this:

V

V

put them equal

div out the 1/3 & 2pi

rh=(r+x)(h-x)

rh=rh+xh-rx-x^2

solve for x