(sqrt2+1)(3sqrt2+1)=? (please explain how to do these)

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
JamesBriggs2011
Posts: 1
Joined: Sun Jul 03, 2011 10:42 pm
Contact:

(sqrt2+1)(3sqrt2+1)=? (please explain how to do these)

Postby JamesBriggs2011 » Sun Jul 03, 2011 11:20 pm

i need to check on my homework??? if someone can explain how to do these it would be appreciated

(sqrt2+1)(3sqrt2+1)=?
sqrt6(sqrt5-sqrt7)=?
sqrt(x+10)=-9 x=? or is there no solution?
(sqr(6mn))to the ninth, rewrite with rqtional exponents
sqrt(9x^)=?
(sqrt3-sqrt8)(sqrt3+sqrt8)=?
9sqrt75-6sqrt3=?

User avatar
maggiemagnet
Posts: 325
Joined: Mon Dec 08, 2008 12:32 am
Contact:

Re: (sqrt2+1)(3sqrt2+1)=? (please explain how to do these)

Postby maggiemagnet » Mon Jul 04, 2011 12:47 am

JamesBriggs2011 wrote:if someone can explain how to do these it would be appreciated

That's what the Purplemath lessons are for!

JamesBriggs2011 wrote:(sqrt3-sqrt8)(sqrt3+sqrt8)=?
9sqrt75-6sqrt3=?
(sqrt2+1)(3sqrt2+1)=?
sqrt6(sqrt5-sqrt7)=?

To learn how to simplify added and multiplied square-root expressions like these, try this lesson.

JamesBriggs2011 wrote:sqrt(x+10)=-9 x=? or is there no solution?

To learn how to solve radical equations, try this lesson.

JamesBriggs2011 wrote:(sqr(6mn))to the ninth, rewrite with rqtional exponents
sqrt(9x^)=?

To learn how to work with rational powers, try this page and this page.

:clap:


Return to “Intermediate Algebra”