## Substituting a negative integer for a variable... exponent

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
zachres
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### Substituting a negative integer for a variable... exponent

I ran across this yesterday in a Pearson intermediate Algebra text.

The problem presented in the text is in regards to graphing ordered pairs. An equation to express the relationship between the pair is given as;

y = 4 - x2

The solution requested is a graph x and y for all pairs where x is an integer from -3 to 3.

For x = -3, the author of the book substituted in this manner;

y = 4 - (-3)2

My question is; why would the substitution not be in this form; y = 4 - (-32)?

The two methods generate different values for x2. The first generates 9, and the second generates -9.

So, again, why one way and not the other?

Martingale
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### Re: Substituting a negative integer for a variable... expone

I ran across this yesterday in a Pearson intermediate Algebra text.

The problem presented in the text is in regards to graphing ordered pairs. An equation to express the relationship between the pair is given as;

y = 4 - x2

The solution requested is a graph x and y for all pairs where x is an integer from -3 to 3.

For x = -3, the author of the book substituted in this manner;

y = 4 - (-3)2

My question is; why would the substitution not be in this form; y = 4 - (-32)?

The two methods generate different values for x2. The first generates 9, and the second generates -9.

So, again, why one way and not the other?
$y=4-x^2$

is the same as

$y=4-(x)^2$

zachres
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Joined: Fri Jun 10, 2011 2:07 pm
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### Re: Substituting a negative integer for a variable... expone

Correct, but

-32

is not the same as

(-3)2

At least according to the text;

-32 = 9

(-3)2 = -9

stapel_eliz
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At least according to the text;

-32 = 9

(-3)2 = -9
Then the text has it backwards!