Tiger wrote:Can anyone help me understand this problem? I need to solve and apply interval notation.
1 < 4x + 3 < 9
How would you solve "4x + 3 = 9"? How about solving "1 = 4x + 3"? You use much the same methods for
solving linear inequalities, even when they have three "halves", as yours does.
For instance:
. . . . .-2 < 3x + 4 < 13
. . . . .-2 - 4 < 3x + 4 - 4 < 13 - 4
. . . . .-6 < 3x < 9
. . . . .(-6)/3 < (3x)/3 < 9/3
. . . . .-2 < x < 3
The "interval notation" presentation of the above solution would be "(-2, 3)". Follow the same pattern with your exercise.