Simplifying (Sick of typing that word): cbrt[(x^0 y^4)/(3z^3  TOPIC_SOLVED

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.

Simplifying (Sick of typing that word): cbrt[(x^0 y^4)/(3z^3

Postby EdSewersPark on Tue May 24, 2011 11:21 pm



Should I do something about the cube roots first?
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Postby stapel_eliz on Wed May 25, 2011 12:51 am

You will need to combine the arguments of the radicals at some point, but that doesn't "have" to be your first step. :wink:
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Re: Simplifying (Sick of typing that word): cbrt[(x^0 y^4)/(

Postby EdSewersPark on Wed May 25, 2011 3:29 pm

Since they are both can I combine them?
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Postby stapel_eliz on Wed May 25, 2011 9:38 pm

EdSewersPark wrote:Since they are both can I combine them?

Yep! :wink:
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Re: Simplifying (Sick of typing that word): cbrt[(x^0 y^4)/(

Postby EdSewersPark on Thu May 26, 2011 10:37 pm



I know 81=27(3) and that 27 is a perfect cube and I think that looks like this do I pull out the x^9 and z^6 so it's ?
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