simplifying [(-2 x^0)/(y^2 z^{-3})]^{-2} x^{-3} y^4 z

EdSewersPark · Postby **EdSewersPark** » Mon May 23, 2011 8:46 pm

$(\frac{-2x^0}{y^2z^-3})^-2$ $(x^-3y^4z)$

I know the correct answer, but I can't get it right.

EdSewersPark · Postby **EdSewersPark** » Mon May 23, 2011 9:00 pm

I am learning the scripts...here it is correctly typed: $(\frac{-2x^0}{y^2z^{-3}})^{-2}$ $x^{-3}y^4z$

stapel_eliz · Postby **stapel_eliz** » Mon May 23, 2011 10:47 pm

EdSewersPark wrote:I am learning the scripts...here it is correctly typed: $(\frac{-2x^0}{y^2z^{-3}})^{-2}$ $x^{-3}y^4z$

What are your steps so far? (If you need to refresh, you can try here.) :wink:

EdSewersPark · Postby **EdSewersPark** » Tue May 24, 2011 12:12 am

Is this correct?

First I flipped the inside and changed the negative exponent (on the outside) to a positive: $(\frac{y^2z^{-3}}{-2x^0})^2$

Then I squared the inside: $(\frac{y^4z^{-6}}{4})$

I put the second part into a fraction: $(\frac{x^{-3}y^4z}{1})$ and flipped the "x": $(\frac{y^4z}{x^3})$

Then multiplied across: $(\frac{y^8z^{-5}}{4x^3})$ and brought the "z" down: $\frac{y^8}{4x^3z^5}$

stapel_eliz · Postby **stapel_eliz** » Tue May 24, 2011 10:42 am

Looks good to me! :wink:

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simplifying [(-2 x^0)/(y^2 z^{-3})]^{-2} x^{-3} y^4 z

simplifying [(-2 x^0)/(y^2 z^{-3})]^{-2} x^{-3} y^4 z

Re: simplifying [(-2 x^0)/(y^2 z^{-3})]^{-2} x^{-3} y^4 z

Re: simplifying [(-2 x^0)/(y^2 z^{-3})]^{-2} x^{-3} y^4 z