Prove that a triangle is rectangular when:( x + y) / 17 = (y + z) / 18 = (z + x) / 25, (with x, y and z as the sides of the triangle).

How to ?

Luke.

Prove that a triangle is rectangular when:( x + y) / 17 = (y + z) / 18 = (z + x) / 25, (with x, y and z as the sides of the triangle).

How to ?

Luke.

How to ?

Luke.

- stapel_eliz
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- Martingale
**Posts:**333**Joined:**Mon Mar 30, 2009 1:30 pm**Location:**USA-
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Luke53 wrote:Prove that a triangle is rectangular when:( x + y) / 17 = (y + z) / 18 = (z + x) / 25, (with x, y and z as the sides of the triangle).

How to ?

Luke.

Find the values for x,y and z

I get for any constant

then show that

door Martingale op wo mei 18, 2011 5:12 am

Luke53 schreef:

Prove that a triangle is rectangular when:( x + y) / 17 = (y + z) / 18 = (z + x) / 25, (with x, y and z as the sides of the triangle).

How to ?

Luke.

Find the values for x,y and z

I get for any constant

then show that

Martingale

Berichten: 363

Geregistreerd op: ma maart 30, 2009 2:30 pm

Woonplaats: USA

OK!

Thats the way to do it. I get the same results setting z = 1 and solve for the two unknows x and y (in function of z)

Never would have thought of this by myself.

Thanks Martingale.

Regards.

Luke.

Luke53 schreef:

Prove that a triangle is rectangular when:( x + y) / 17 = (y + z) / 18 = (z + x) / 25, (with x, y and z as the sides of the triangle).

How to ?

Luke.

Find the values for x,y and z

I get for any constant

then show that

Martingale

Berichten: 363

Geregistreerd op: ma maart 30, 2009 2:30 pm

Woonplaats: USA

OK!

Thats the way to do it. I get the same results setting z = 1 and solve for the two unknows x and y (in function of z)

Never would have thought of this by myself.

Thanks Martingale.

Regards.

Luke.