Dividing Rational Expressions

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
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Dividing Rational Expressions

Postby onmyown » Sat May 07, 2011 8:50 pm

Hi, can someone please help me understand how this problem is solved?

This is the problem: Image

This is as far as I get (multiply first fraction by reciprocal of second fraction):
(ignore the red question mark)

I understand the steps and how to divide rational expressions (including this one). I just don't know how I should simplify the numerator in this case.
I know the answer. It is:

Particularly I don't understand how x^2-6x+15 became (x-5)(x-1). Because, (x-5)(x-1)= x^2-6x-5 and not x^2-6x+15. Can someone please explain how the numerator was simplified?

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Postby stapel_eliz » Sat May 07, 2011 10:48 pm

My guess is that the original "15" was a typo for "5". :wink:

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