Complex equation graphing help!

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Complex equation graphing help!

Postby jboykin325 on Thu Mar 03, 2011 8:00 pm

I am struggling on how to graph the following equations, and i don't know what steps to take to begin.

[(x-2)/3] - [(5)/(2y-4)] = 0

and

y= x^3 + 3x^2 - 6x

What are the steps used in order to graph these equations?

Thanks.
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Postby stapel_eliz on Thu Mar 03, 2011 10:23 pm

jboykin325 wrote:I am struggling on how to graph the following equations, and i don't know what steps to take to begin.

Use steps similar to what you've used for other graphs; namely, pick some x-values, plug them into the equation, solve for the corresponding y-values, and draw the dots. Continue until you have a good idea of what the graph should look like. Then draw in the line(s).

jboykin325 wrote:[(x-2)/3] - [(5)/(2y-4)] = 0

It might be simplest to solve this, once and for all, for "y=". Then plug x-values in, etc, just as you always have for graphing linear equations.

jboykin325 wrote:y= x^3 + 3x^2 - 6x

A potentially-useful extra step here might be to take the common factor out front and then factor the remaining quadratic. From this, you can find the x-intercepts easily. Then proceed (with plotting points, etc) as usual. :wink:
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Re: Complex equation graphing help!

Postby jboykin325 on Fri Mar 04, 2011 8:08 pm

Yes, but how do you find the asymtotes?

and thank you for replying to all of my posts! :]
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Postby stapel_eliz on Fri Mar 04, 2011 9:42 pm

jboykin325 wrote:Yes, but how do you find the asymtotes?

What asymptotes? For which? :confused:
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Re: Complex equation graphing help!

Postby jboykin325 on Tue Mar 08, 2011 7:54 pm

for this :

[(x-2)/3] - [(5)/(2y-4)] = 0


I have all of the answers, and it shows that there is an asymptote at y=2

:[
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