## Complex equation graphing help!

Quadratic equations and inequalities, variation equations, function notation, systems of equations, etc.
jboykin325
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Joined: Thu Mar 03, 2011 7:53 pm
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### Complex equation graphing help!

I am struggling on how to graph the following equations, and i don't know what steps to take to begin.

[(x-2)/3] - [(5)/(2y-4)] = 0

and

y= x^3 + 3x^2 - 6x

What are the steps used in order to graph these equations?

Thanks.

stapel_eliz
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Joined: Mon Dec 08, 2008 4:22 pm
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I am struggling on how to graph the following equations, and i don't know what steps to take to begin.
Use steps similar to what you've used for other graphs; namely, pick some x-values, plug them into the equation, solve for the corresponding y-values, and draw the dots. Continue until you have a good idea of what the graph should look like. Then draw in the line(s).
[(x-2)/3] - [(5)/(2y-4)] = 0
It might be simplest to solve this, once and for all, for "y=". Then plug x-values in, etc, just as you always have for graphing linear equations.
y= x^3 + 3x^2 - 6x
A potentially-useful extra step here might be to take the common factor out front and then factor the remaining quadratic. From this, you can find the x-intercepts easily. Then proceed (with plotting points, etc) as usual.

jboykin325
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Joined: Thu Mar 03, 2011 7:53 pm
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### Re: Complex equation graphing help!

Yes, but how do you find the asymtotes?

and thank you for replying to all of my posts! :]

stapel_eliz
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Joined: Mon Dec 08, 2008 4:22 pm
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Yes, but how do you find the asymtotes?
What asymptotes? For which?

jboykin325
Posts: 7
Joined: Thu Mar 03, 2011 7:53 pm
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### Re: Complex equation graphing help!

for this :

[(x-2)/3] - [(5)/(2y-4)] = 0

I have all of the answers, and it shows that there is an asymptote at y=2

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