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`f(x) = sqrt(x - 2) + 6`

and have come up with the domain x=> 2. I also have the pairs (2,6)(3,7)(6,8)(11,9(18,10). Graphing this makes it obvious that there is not an x intercept.

But if I take the equation and set the numerator to zero and solve...

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` 0 = sqrt(x - 2) + 6`

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0 = sqrt(x - 2) + 6

-6 = sqrt(x - 2)

-6^2] = ( sqrt(x - 2) ) ^2

36 = x - 2

34 = x

Anyone???