mitnord wrote:Following your steps I found that:
-1 = c and
-a = -b
What to do next? I was only given the two points: (0, -1) and (1, 1) and that the parabola is symmetrical around y-axis. Is it even possible?
c = -1 is correct, but -a = -b isn't. I think you may have made a mistake when dealing with the sign of c.
From the point (1, 1), x = 1 and y = 1
So, since for a parabola:
y = ax
^{2} + bx + c
(1) = a(1)
^{2} + b(1) + c
1 = a + b + c
And from the previous equation, c = -1, so
1 = a + b + (-1) <-- Need to be careful with the minus sign here
1 = a + b - 1
Add 1 to both sides:
1 + 1 = a + b - 1 + 1
2 = a + b
Subtract b from both sides:
2 - b = a + b - b
2 - b = a
So, a = 2 - b
As Eliz has said, the key piece of information to find the
third point is that the parabola is symmetrical around the y-axis. That is, the vertical axis acts like a mirror, and any points to the right of it will be reflected and appear the same distance to the left of it.
The point (0, -1), where x = 0, lies
on the axis of symmetry, that is, it is no distance away from it, so its reflection would also be no distance away and therefore would be in the same place, (0, -1). This doesn't tell us anything new, so we can ignore it.
However, the point (1,1) does
not lie on the axis of symmetry, so how far away will its reflection be? And since reflecting horizontally doesn't change anything vertically, the y-coordinate will stay the same.
So, from this information, what will be the coordinates of the reflection of (1,1)? This will be your third point which you can then use as outlined by Eliz above.
DAiv