This is the beginning of our algebra course and I am already lost! This seems so simple, solve for x in terms of y:

4x^2-2xy+3y^2=2

I can't figure out how to isolate x on one side. The y keeps popping up! Help please!

This is the beginning of our algebra course and I am already lost! This seems so simple, solve for x in terms of y:

4x^2-2xy+3y^2=2

I can't figure out how to isolate x on one side. The y keeps popping up! Help please!

4x^2-2xy+3y^2=2

I can't figure out how to isolate x on one side. The y keeps popping up! Help please!

- stapel_eliz
**Posts:**1733**Joined:**Mon Dec 08, 2008 4:22 pm-
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Mumina wrote:...solve for x in terms of y: 4x^2-2xy+3y^2=2

The trick here is to view this as a quadratic in y:

. . . . .3

You can apply

. . . . .

...and so forth.

You will get "y=" two different things, one from the "plus" and the other from the "minus" of the "plus / minus" in the Formula.