Solving this equation by substitution, It my work correct?

[illuminati58]

Can someone please tell if i am doing this right! Please!
x + Y = 6
2x + y =8

2x + y = 8
x + y = 6
x = -y + 6

2 (-y + 6) + y = 8
2y + 12 + y = 8
3y + 12 = 8
3y = - 4
y = -4/3

X = -y + 6
X = -(-4/3) + 6
x = 4/3 + 6
x = 4/3 + 6

{( 12, 4/3 +6 )}

[stapel_eliz]

2 (-y + 6) + 4 = 8

Where did the "4" come from?

[illuminati58]

Sorry it was a typo but my answer doesnt seem correct
x + Y = 6
2x + y =8

2x + y = 8
x + y = 6
x = -y + 6

2 (-y + 6) + y = 8
2y + 12 + y = 8
3y + 12 = 8
3y = - 4
y = -4/3

X = -y + 6
X = -(-4/3) + 6
x = 4/3 + 6
x = 4/3 + 6

{( 12, 4/3 +6 )}

[illuminati58]

What about this solution for the same problem?

x + y = 6
2x + y = 8

x= -y + 6
2(-y+6) + y = 8
- 2y -12 + y = 8
y - 12 = 8
y = 16

x = -y + 6
x = (-16) + 6
x = 16 + 6
x = 22

{(22, 16)}

[stapel_eliz]

2 (-y + 6) + y = 8
2y + 12 + y = 8

How did (2)(-y) become 2y?