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by **prnygboy1** on Wed Jun 24, 2009 6:59 am

Who can walk me thru the steps please
x^2-11x+24=0 solve for x and 8x^2+2x-15=0 solve for x Help :confused:

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by **stapel_eliz** on Wed Jun 24, 2009 11:06 am

prnygboy1 wrote:Who can walk me thru the steps please

This lesson will walk you through the steps. :wink:

. . . . . $x^2\, -\, 11x\, +\, 12\, =\, 0$

. . . . . $\mbox{move the constant: }x^2\, -\, 11x\, =\, -12$

. . . . . $\mbox{square half of linear coeff; add: }x^2\, -\, 11x\, +\, \frac{121}{4}\, =\, -12\, +\, \frac{121}{4}$

. . . . . $\mbox{restate as square: }\left(x\, -\, \frac{11}{2}\right)^2\, =\, \frac{121\, -\, 48}{4}$

...and so forth.

Once you've learned those steps, please attempt the exercises. If you get stuck, you can then reply with a clear listing of your steps and reasoning so far. Thank you!

The Purplemath Forums

Complete the Square solving for x

Complete the Square solving for x