mizkej wrote:Write the equation ( in slope-intercept form ) of the line through (6, -2) with the slope 1/3.
To learn, in general, how to find line equations when given a slope and a point (or just two points), try here
Then note that you have the point (x1
) = (6, -2) and the slope m = 1/3. These will plug nicely into the "point-slope form": y - y1
= m(x - x1
So plug the given values into the given formula, and solve for "y="
to convert point-slope form into slope-intercept form.
If you get stuck, please reply showing how far you have gotten. Thank you!