Stuck on rearranging of this equation  TOPIC_SOLVED

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Stuck on rearranging of this equation

Postby tobriain on Fri Jul 05, 2013 2:10 pm

Hi,

I need to get from

[(1-p)f+p(1-f)](1+v)-[(1-p)(1-f)+pf] = x

to (2+v)(f+p-2pf)-1 = x

but I'm stuck. I'd appreciate any tips on what I should I do after the following.

(f+p-2pf)(1+v) + (f + p - 2pf) - 1 = x

Thanks in advance.
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  TOPIC_SOLVED

Postby stapel_eliz on Fri Jul 05, 2013 7:37 pm

tobriain wrote:I need to get from

[(1-p)f+p(1-f)](1+v)-[(1-p)(1-f)+pf] = x

to (2+v)(f+p-2pf)-1 = x

but I'm stuck. I'd appreciate any tips on what I should I do after the following.

(f+p-2pf)(1+v) + (f + p - 2pf) - 1 = x

You've done the hard part. Now do the easy last step: Factor out the common expression from each of the first two "terms":

. . . . .(1 + v)(f + p - 2pf) + (1)(f + p - 2pf)

Simplify what's left, and you're done! :wink:
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