plz help me simplify F=A'.B'(A.B+B')

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plz help me simplify F=A'.B'(A.B+B')

Postby ALI on Fri Jun 14, 2013 7:03 am

As I am new in this plz can some one help me to simplify this expression ,i try but i am not sure is it corect or wrong.
expression is
F=A'.B'(A.B+B')

F=A'.B'(AB+B')
F=A'.B'(A+B+B') BY USING DEMORGAN LAW
F=A'.B'(A+(B+B')) By rearranging above expression
F=A'.B'(A+1) BY USING RULE#11
F=A'.B' BY USING RULE #5
F=(A+B)'
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Re: plz help me simplify F=A'.B'(A.B+B')

Postby maggiemagnet on Fri Jun 14, 2013 2:44 pm

ALI wrote:As I am new in this plz can some one help me to simplify this expression...
F=A'.B'(A.B+B')

Does the "prime" notation (the apostrophe after the letters) mean "not", or "complement", or something else? What does "plus" mean? What does the "dot" mean? Is there any "priority" so, say, the "dot" binds more tightly than does the "plus" -- so A.B+B' means (A.B)+B'? Thanks!
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Re: plz help me simplify F=A'.B'(A.B+B')

Postby ALI on Fri Jun 14, 2013 4:59 pm

Dear this ' is compliment dot means AND gate and plus means OR gate
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Re: plz help me simplify F=A'.B'(A.B+B')

Postby maggiemagnet on Sat Jun 15, 2013 12:21 pm

ALI wrote:Dear this ' is compliment dot means AND gate and plus means OR gate

From "gate" I'm going to guess that you're doing circuits, etc, like they talk about here that "complement" means logical "not". I'm assuming that the "math" stuff follows the usual order of operations rules so you have this:

(not-A and not-B) and ([A and B] or not-B)

Are there any rules here that you're not allowed to use? Thanks!
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