Helping students gain understanding and self-confidence in algebra.
santaclaus wrote:A circle of radius 2 is centered at the origin and goes through the point (-1 sqare root of 3)
1. find an equation for the line through the origin and the point (-1, square root of 3)
santaclaus wrote:2. find an equation for the tangent line to the circle at the radius at the point of tangency -- no idea what this means?
santaclaus wrote:so, would I do, square root 3 = -1 + b? then b=square root 3 +1?
put it into the equation after finding slope like so? y=1/square root 3 + square root 3 +1?
santaclaus wrote:btw, I found slope to be 0- -1/0-square root 3 = -1/square root 3 and perpendicular slope is just square root 3