^{2}+q

^{2}= 25 and 2pq=10, what is (p-q)

^{2}?

a)250

b)100

c)50

d) 5

i dont get this...the answer is b) and i guessed c).

i only know that pq=5 and possible values for the p and q in p

^{2}+q

^{2}= 25 are p=4 and q=3 or vice versa.

if p^{2}+q^{2}= 25 and 2pq=10, what is (p-q)^{2}?

a)250

b)100

c)50

d) 5

i dont get this...the answer is b) and i guessed c).

i only know that pq=5 and possible values for the p and q in p^{2}+q^{2}= 25 are p=4 and q=3 or vice versa.

a)250

b)100

c)50

d) 5

i dont get this...the answer is b) and i guessed c).

i only know that pq=5 and possible values for the p and q in p

i'm surprised nobody answered this. you need to use the perfect squares formula: (p-q)^2 = p^2-2pq+q^2

then p^2+q^2-2pq = 25-10 = 15 = (p-q)^2

i think all the answers are wrong

then p^2+q^2-2pq = 25-10 = 15 = (p-q)^2

i think all the answers are wrong