Can't solve this one, so please help.

A train is travelling from A to B. After it travelled for one hour, it stops for one hour and then continues it's voyage with a speed that is equal of 3/5 of the initial speed. It arrives at B with a delay of 3 hours . If the train would have stopped 50 km further than the point where it first stopped, it would have arrived 1h 40 min earlier. Find the initial speed and the distance between A and B.

Sorry, made a correction, (I forgot something, the train stops for one hour).

I think I finally found the solution, the initial speed would be 50 km/h and the distance between A and B 275 km, (and the travelling time without delay would be 5.5 hours).

Anyway, thanks for the help, (and sorry for ignoring the one hour stopping time of the train in this word problem).

Greetszzz.

Luke.