by Luke53 on Sun Mar 13, 2011 8:23 pm
OK, thanks for the relply, I know thanks to the Wikipedia factoring page you send me, how to solve this problem now.
I divide each term by 5 to get 8x^3 - 1 that turns in to (2x)^3 - 1^3, then 2x - 1 is a factor, the other factor is found by long division of (2x^3 - 1)/ (2x - 1) = 4x^2 + 2x + 1. I now have to multiply one of the factors by 5 again to make up for the first division by 5. So 40x^3 - 5 = 5 (2x -1) (4x^2 + 2x + 1).
Thank you very much for your help.
Greetings.
Luke.