Hi, I am having trouble solving this problem. I have made at least 4-5 attempts on it by now. Can someone please help me out?
Here is the problem: A number consists of two digits. 13 more than 7 times the units digits is 3 times the tens digit. If the digits are reversed, 2 times the new number is 34 less than the original number. Find the number.
Here is one my of attempts:
- Translated each statement into equations:
"13 more than 7 times the units digits is 3 times the tens digit." --> 13+7u=3t
"If the digits are reversed, 2 times the new number is 34 less than the original number" --> 2(10u+t)=10t+u-34
- Made all variables on one side of each equation, and made a system of equations:
- Solved the system of equations, to solve for u:
3 * (8t+19u = -34) ------> 24t+57u=-102
8 * (3t - 7u = 13) ------> - 24t - 56u=104
113u/113 = -206/113
Therefore, u= -1.8
- Substituted value of u into other equation, to solve for t:
I know all that is wrong. The answer is supposedly 92. I'd appreciate any help, thanks