I am trying to solve the following linear program using the graphical solution procedure:

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

I am trying to solve the following linear program using the graphical solution procedure:

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

needhelp2 wrote:I am trying to solve the following linear program using the graphical solution procedure...

Okay. How far have you gotten?

You started with assigning each variable to an axis (say, the A variable to the x-axis and the B variable to the y-axis),

Please be complete. Thank you!

Yes I need to graph and solve the equation.

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

1A<= 100 is a vertical line on the graph (I think it is vertical, but I am not sure. My reasoning is A is on the X axis)

another question about my graph; starting from the Orgin if "0" do I start my numbers at 100, 200, 300 ... or since the distance is so close should I do in increments of 10s --- 10,20, 30 Is there a rule of thumb for this?

1B<= 80 is a horizontal line on the graph

2A + 4B <= 400 here is where I am stuck.

to solve I substitue "0" for both A and B each time and I get the following points

(200,0)

(0,100)

I plot both of these points. My extreme points are (100,50) and (40,80)

where do I go from here, not sure what this means as it relates to 5A + 5B.

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

1A<= 100 is a vertical line on the graph (I think it is vertical, but I am not sure. My reasoning is A is on the X axis)

another question about my graph; starting from the Orgin if "0" do I start my numbers at 100, 200, 300 ... or since the distance is so close should I do in increments of 10s --- 10,20, 30 Is there a rule of thumb for this?

1B<= 80 is a horizontal line on the graph

2A + 4B <= 400 here is where I am stuck.

to solve I substitue "0" for both A and B each time and I get the following points

(200,0)

(0,100)

I plot both of these points. My extreme points are (100,50) and (40,80)

where do I go from here, not sure what this means as it relates to 5A + 5B.

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

needhelp2 wrote:Yes I need to graph and solve the equation.

To learn how to graph the solutions to systems of linear inequalities, please study

needhelp2 wrote:1A<= 100 is a vertical line on the graph (I think it is vertical, but I am not sure. My reasoning is A is on the X axis)

Yes.

needhelp2 wrote:another question about my graph; starting from the Orgin if "0" do I start my numbers at 100, 200, 300 ... or since the distance is so close should I do in increments of 10s --- 10,20, 30

I think the above refers to the numbering on the axes. If so, then use whatever units

needhelp2 wrote:1B<= 80 is a horizontal line on the graph

Yes.

needhelp2 wrote:2A + 4B <= 400 here is where I am stuck.

Solve the inequality for whichever variable you've put on the y-axis. (To learn how to solve linear equations for "y", try

needhelp2 wrote:My extreme points are (100,50) and (40,80) where do I go from here, not sure what this means as it relates to 5A + 5B.

Then you plug the extreme points into the optimization equation, and see which one is the best fit to the requirements of the exercise. For worked examples, please review