I am trying to solve the following linear program using the graphical solution procedure:

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

I am trying to solve the following linear program using the graphical solution procedure:

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

Okay. How far have you gotten?I am trying to solve the following linear program using the graphical solution procedure...

You started with assigning each variable to an axis (say, the A variable to the x-axis and the B variable to the y-axis),

Please be complete. Thank you!

Yes I need to graph and solve the equation.

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

1A<= 100 is a vertical line on the graph (I think it is vertical, but I am not sure. My reasoning is A is on the X axis)

another question about my graph; starting from the Orgin if "0" do I start my numbers at 100, 200, 300 ... or since the distance is so close should I do in increments of 10s --- 10,20, 30 Is there a rule of thumb for this?

1B<= 80 is a horizontal line on the graph

2A + 4B <= 400 here is where I am stuck.

to solve I substitue "0" for both A and B each time and I get the following points

(200,0)

(0,100)

I plot both of these points. My extreme points are (100,50) and (40,80)

where do I go from here, not sure what this means as it relates to 5A + 5B.

Max 5A + 5B

s.t.

1A < or = 100

1B < or = 80

2A + 4B < or = 400

A,B >or = 0

1A<= 100 is a vertical line on the graph (I think it is vertical, but I am not sure. My reasoning is A is on the X axis)

another question about my graph; starting from the Orgin if "0" do I start my numbers at 100, 200, 300 ... or since the distance is so close should I do in increments of 10s --- 10,20, 30 Is there a rule of thumb for this?

1B<= 80 is a horizontal line on the graph

2A + 4B <= 400 here is where I am stuck.

to solve I substitue "0" for both A and B each time and I get the following points

(200,0)

(0,100)

I plot both of these points. My extreme points are (100,50) and (40,80)

where do I go from here, not sure what this means as it relates to 5A + 5B.

- stapel_eliz
**Posts:**1628**Joined:**Mon Dec 08, 2008 4:22 pm-
**Contact:**

To learn how to graph the solutions to systems of linear inequalities, please studyYes I need to graph and solve the equation.

Yes.1A<= 100 is a vertical line on the graph (I think it is vertical, but I am not sure. My reasoning is A is on the X axis)

I think the above refers to the numbering on the axes. If so, then use whatever unitsanother question about my graph; starting from the Orgin if "0" do I start my numbers at 100, 200, 300 ... or since the distance is so close should I do in increments of 10s --- 10,20, 30

Yes.1B<= 80 is a horizontal line on the graph

Solve the inequality for whichever variable you've put on the y-axis. (To learn how to solve linear equations for "y", try2A + 4B <= 400 here is where I am stuck.

Then you plug the extreme points into the optimization equation, and see which one is the best fit to the requirements of the exercise. For worked examples, please reviewMy extreme points are (100,50) and (40,80) where do I go from here, not sure what this means as it relates to 5A + 5B.