please help... (x+5)-2(4x-1)=0
I cant remember how to solve for x!!!
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can't remember how to solve (x+5)-2(4x-1)=0 
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can't remember how to solve (x+5)-2(4x-1)=0
by angelajoyner31 on Tue Apr 24, 2012 1:46 pm
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Re: can't remember how to solve (x+5)-2(4x-1)=0
by buddy on Wed Apr 25, 2012 12:12 pm
angelajoyner31 wrote:please help... (x+5)-2(4x-1)=0
I cant remember how to solve for x!!!
you can see how here. if your having trouble with the brackets, try this article on "simplifying w/ parentheses". the 1st step will be x+5-8x+2=0
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Re: can't remember how to solve (x+5)-2(4x-1)=0 
by MrAlgebra on Sun Sep 16, 2012 4:07 am
Start off by simplifying everything that you can. Maybe try multiplying out the -2(4x-1) part? 
(x + 5) - 2(4x - 1) = 0
x + 5 - 8x + 2 = 0
Don't forget that you have to multiply out by -2 instead of just 2, so you'll get -8x + 2 instead of 8x - 2.
From there, you can simplify some more and try to get x by itself so you have something that looks like x = ___ that tells you the answer.
(x + 5) - 2(4x - 1) = 0
x + 5 - 8x + 2 = 0
Don't forget that you have to multiply out by -2 instead of just 2, so you'll get -8x + 2 instead of 8x - 2.
From there, you can simplify some more and try to get x by itself so you have something that looks like x = ___ that tells you the answer.
-
MrAlgebra - Posts: 11
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