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Please help having a difficult time solving this problem! The perimeter of a rectangle is 58 inches. The length exceeds the width by 19 inches. Find the length and width.

- phansen05
**Posts:**9**Joined:**Mon Jan 17, 2011 3:54 am

phansen05 wrote:Please help having a difficult time solving this problem! The perimeter of a rectangle is 58 inches. The length exceeds the width by 19 inches. Find the length and width.

The formula for perimeter is P = 2L + 2W

You know that P = 58 and W + 19 = L

Replace the L in the first equation with (W + 19)

Solve for W and then add 19 to get L.

- snowdrifter
**Posts:**20**Joined:**Tue Jan 11, 2011 4:52 pm

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