A carload of campers leaves for a lake at 8 AM. a second carload leaves at 8:30 AM and drives 10 mph faster over the same road.

if the second car overtakes the first at 10:30 AM , what's the average speed of each car?

R x T= D

HELP PLEASE & EXPLAIN

R x T= D

A carload of campers leaves for a lake at 8 AM. a second carload leaves at 8:30 AM and drives 10 mph faster over the same road.

if the second car overtakes the first at 10:30 AM , what's the average speed of each car?

R x T= D

- stapel_eliz
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xxcelloxx wrote:A carload of campers leaves for a lake at 8 AM. a second carload leaves at 8:30 AM and drives 10 mph faster over the same road. if the second car overtakes the first at 10:30 AM , what's the average speed of each car?

To learn the basic set-up and process for "uniform rate" exercises, try

. . .first car:

. . . . .rate: r

. . . . .time: 2.5

. . . . .distance: 2.5r

. . .second car:

. . . . .rate: r + 10

. . . . .time: ??

. . . . .distance: ??

Complete the table. Then, since the distances are the same, set the "distance" expressions equal, and solve.