equation: 17-x = 41, -(6-3)^5, 14-3^5 / 3x3^3

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kyl367
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Joined: Thu Feb 18, 2010 2:12 am
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equation: 17-x = 41, -(6-3)^5, 14-3^5 / 3x3^3

Postby kyl367 » Thu Feb 18, 2010 2:32 am

1) 17-x = 41
17-x + x =41+x = 17-41= 41-41+x= x= -24 Is this correct?

2) -(6-3)^5
-(3)^5 = -(3^5) = -243 Is this corrrect?

3)14-3^5 ÷ 3x3^3
14-243 ÷ 3x27
14-81x27=
14-2187= -2173 Is this correct?

Thanks

Howdy
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Joined: Mon Feb 01, 2010 4:34 pm
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Re: equation

Postby Howdy » Thu Feb 18, 2010 4:53 am

Try using the pre tags to enclose and line up your work more neatly. 

1)
17-x = 41
-17 -17 <-- subtract 17 from both sides of equation
-x = 24 <-- leaves you with this
*(-1) *(-1) <-- convert x to positive by multiplying each by -1
x = -24

17-(-24) = 41 ?? <-- check answer ...true??

Your other two answers look correct to me.


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